3(1^2)-25y^2=2

Solution for 3(1^2)-25y^2=2 equation:

3(1^2)-25y^2=2

We move all terms to the left:

3(1^2)-25y^2-(2)=0

determiningTheFunctionDomain
-25y^2-2+31^2=0

We add all the numbers together, and all the variables

-25y^2+959=0

a = -25; b = 0; c = +959;
Δ = b2-4ac
Δ = 02-4·(-25)·959
Δ = 95900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{95900}=\sqrt{100*959}=\sqrt{100}*\sqrt{959}=10\sqrt{959}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{959}}{2*-25}=\frac{0-10\sqrt{959}}{-50}
=-\frac{10\sqrt{959}}{-50}
=-\frac{\sqrt{959}}{-5}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{959}}{2*-25}=\frac{0+10\sqrt{959}}{-50}
=\frac{10\sqrt{959}}{-50}
=\frac{\sqrt{959}}{-5}
$